c^2+12c+27=0

Solution for c^2+12c+27=0 equation:

Simplifying
c2 + 12c + 27 = 0

Reorder the terms:
27 + 12c + c2 = 0

Solving
27 + 12c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(9 + c)(3 + c) = 0

Subproblem 1
Set the factor '(9 + c)' equal to zero and attempt to solve:

Simplifying
9 + c = 0

Solving
9 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + c = 0 + -9

Combine like terms: 9 + -9 = 0
0 + c = 0 + -9
c = 0 + -9

Combine like terms: 0 + -9 = -9
c = -9

Simplifying
c = -9
Subproblem 2
Set the factor '(3 + c)' equal to zero and attempt to solve:

Simplifying
3 + c = 0

Solving
3 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + c = 0 + -3
c = 0 + -3

Combine like terms: 0 + -3 = -3
c = -3

Simplifying
c = -3
Solution
c = {-9, -3}